Potential Energy of an Electron in a Battery

Click For Summary
SUMMARY

An electron moving from the positive to the negative terminal of a 9V battery experiences a change in potential energy calculated using the formula ΔU = qΔV. The correct interpretation is that the electron gains energy when moving from a higher potential (+9V) to a lower potential (0V). This is because the charge of the electron is negative, leading to a positive change in potential energy when the signs of charge and potential difference are considered. The discussion clarifies misconceptions about energy gain and loss in this context.

PREREQUISITES
  • Understanding of electric potential and potential difference
  • Familiarity with the concept of charge (q) and its sign
  • Basic knowledge of energy equations in physics
  • Ability to interpret battery behavior in electrical circuits
NEXT STEPS
  • Study the relationship between electric potential and potential energy in detail
  • Learn about the behavior of electrons in electric fields
  • Explore the principles of battery operation and charging processes
  • Investigate the implications of charge sign on energy calculations
USEFUL FOR

Physics students, electrical engineers, and anyone interested in understanding the principles of electric potential and energy transfer in batteries.

erisedk
Messages
372
Reaction score
7

Homework Statement


An electron moves from the positive to the negative terminal of a battery (9V). How much potential energy did it gain or lose?

Homework Equations

The Attempt at a Solution


Solving for the amount is basic. That's just qV = 14.4 * 10^-19 J
I'm not sure whether it will gain the energy or lose it.
I believe that since the positive terminal is at a higher potential, a positive charge would lose energy, and therefore, the electron will gain energy. But the answer at the back says that it would lose energy. I'm not sure what's wrong.
 
Physics news on Phys.org
Wouldn't it take work to move an electron away from a positive charge?
 
erisedk said:
That's just qV

The more general relation is ##\Delta U=q \ \Delta V## where ##\Delta V## is the change in potential. If ##q## and ##\Delta V## have different signs, then ##\Delta U## is negative. If they have the same sign then ##\Delta U## is positive.
 
erisedk said:
An electron moves from the positive to the negative terminal of a battery (9V).

you are starting with an incorrect assumption
try again
 
No he isn't. The problem statement ask what happens if an electron moves from positive to negative. That occurs when a battery is being charged.
 
CWatters said:
No he isn't. The problem statement ask what happens if an electron moves from positive to negative.

we shouldn't nitpick :wink:
he didn't say what if ... he stated it as a fact :wink:

An electron moves from the positive to the negative terminal of a battery

this isn't likely to happen as it goes against the current flow

Noting that he hasn't stated if this is internal or external to the battery ... the norm being an external reference
battery charging also wasn't mentionedTo the OP
you need to write a clearer idea of what you are referring to, to stop the ambiguity :smile:D
 
The OP didn't state this, he's just trying to understand the statement he was given and answer a question about it. It makes no difference how the electron gets there. The positive terminal is at a potential of +9 volts relative to the negative terminal. An electron in the latter location has how much potential energy relative to an electron in the former location? That's an equivalent question.
 
  • Like
Likes   Reactions: CWatters and erisedk

Similar threads

  • · Replies 10 ·
Replies
10
Views
2K
Replies
5
Views
2K
  • · Replies 12 ·
Replies
12
Views
1K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
9
Views
1K
  • · Replies 44 ·
2
Replies
44
Views
5K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
4
Views
2K