Potential energy of spring and mass system

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SUMMARY

The discussion centers on calculating the potential energy of a system consisting of three equal masses connected by springs, each with a length of 'a' and a spring constant 'k'. The correct potential energy equation is established as U = (1/2) k [(x2 - x1 - a)² + (x3 - x2 - a)²]. A practical example using x1 = -100, x2 = -99, and a = 1 meters demonstrates that the spring between the first and second masses is not stretched, confirming the validity of the equation.

PREREQUISITES
  • Understanding of Hooke's Law and spring constants
  • Familiarity with potential energy concepts in physics
  • Basic knowledge of algebraic manipulation
  • Ability to visualize and analyze one-dimensional mass-spring systems
NEXT STEPS
  • Explore advanced topics in oscillatory motion and energy conservation
  • Learn about coupled oscillators and their potential energy equations
  • Investigate the effects of varying spring constants on system dynamics
  • Study numerical methods for simulating mass-spring systems
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Students studying classical mechanics, physics educators, and anyone interested in understanding the dynamics of mass-spring systems and potential energy calculations.

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Homework Statement



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There are 3 equal masses connected by springs with length a and spring constant k.

The system can only move in the x axis.
x1,x2,x3 is the position of each massWhat is the potential of the system?

The Attempt at a Solution



I came up with this equation:

U=\frac{1}{2} k [(a-x2-x1)^2 + (a-x3-x2)^2]

is it right? thanks
 
Last edited:
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Try x_1 = -100, x_2 = -99, a=1 (in meters if you like). Clearly the spring between 1 and 2 is not stretched (it has rest length 1 and the distance between the points is 1). What does your function give for that spring? Can that be right?
 
U=\frac{1}{2} k [(x2-x1-a)^2 + (x3-x2-a)^2]

got it
 

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