Potential energy of string and rock

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SUMMARY

The discussion focuses on a pendulum problem involving a small rock with a mass of 0.12 kg attached to a massless string of length 0.8 m, swinging at a maximum angle of 45 degrees. Key calculations include determining the speed of the rock at the vertical position and the tension in the string at both 45 degrees and the vertical. The elevation change, represented as "y" in the potential energy equation U = mgy, is derived from the geometry of the pendulum, specifically as l(1 - cos θ), where l is the string length and θ is the angle from the vertical.

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  • Understanding of basic physics concepts such as potential energy and kinetic energy.
  • Familiarity with pendulum motion and angular displacement.
  • Knowledge of trigonometric functions, particularly sine and cosine.
  • Ability to apply Newton's laws of motion in circular motion scenarios.
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  • Study the principles of pendulum dynamics and energy conservation.
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  • Explore the relationship between angular displacement and linear motion in circular paths.
  • Investigate the effects of tension in strings during pendulum motion at different angles.
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Students studying physics, particularly those focusing on mechanics and pendulum motion, as well as educators seeking to clarify concepts related to energy transformations in pendulums.

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hi, I am new here..can you please help me understand this problem below? actually i have the solution already but i don't get it..sorry I am so stupid..

here's the problem:
A small rock with mass .12 kg is fastened to a massless string with length .8 m to form a pendulum. The pendulum is swinging so as to make a maximum angle of 45 degrees with the vertical. Air resistance is negligible. a) What is the speed of the rock when the string passes through the vertical position? b) What is the tension in the string when it makes an angle of 45 degrees with the vertical? c) What is the tension in the string as it passes through the vertical?

the solution is in the attached file...

the problem is i don't know how the "y" in the U = mgy became l( 1- cos theta). that's the only thing i don't understand. I am really poor when it comes to problems involving angles. please bear with me...
 

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The y is simply the elevation from the lowest point of the rock (mass) when it swings in the circular trajectory. In the vertical position, the rock is at a distance l from the pivot (other end of the massless string). As the string and rock rotate (angle [itex]\theta[/itex]) from the vertical, the elevation increases l - projection of l to the vertical.

Let l be the hypotenuse of a triangle, then determine the projection (length) onto the vertical based on the angle [itex]\theta[/itex] between l and the vertical.
 

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