Potential Energy of the Atmosphere

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Using the hydrostatic relationship to express density (rho) and height (z) in terms of pressure (p) may not be effective for solving the question. Familiarity with the ideal gas law is suggested as a more useful approach. The discussion emphasizes the importance of providing more context and effort in queries, as per forum guidelines. Participants are encouraged to engage more deeply with the problem rather than simply stating difficulties. Overall, a more thorough understanding of relevant principles is necessary for progress.
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Summary:: I have been trying to do this question for a while using the hydrostatic relationship to put rho and z in terms of p, however, I can not seem to end up with an answer. Can anyone suggest where to start.

The question is as follows:
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Helli @boopdebeep ,
:welcome: ##\qquad# !​
using the hydrostatic relationship to put rho and z in terms of p
might not be so useful. Do you know about the ideal gas law ?

btw: PF rules ask a bit more from you than just 'can't find an answer' ... :frown:

##\ ##
 

Thread 'Bernoulli vs real life experiment'

If have close pipe system with water inside pressurized at P1= 200 000Pa absolute, density 1000kg/m3, wider pipe diameter=2cm, contraction pipe diameter=1.49cm, that is contraction area ratio A1/A2=1.8 a) If water is stationary(pump OFF) and if I drill a hole anywhere at pipe, water will leak out, because pressure(200kPa) inside is higher than atmospheric pressure (101 325Pa). b)If I turn on pump and water start flowing with with v1=10m/s in A1 wider section, from Bernoulli equation I...
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