The problem is asking you to compare the electric potential energy between two cases. It doesn't give you numbers, though, so you can't work out a specific amount of energy for each case. Your expressions will be in terms of q, the magnitude of the charge on each ball, and R, the initial distance between them.
The balls are oppositely charged, so if one ball has charge q, the other has charge -q. The distance between them initially is R, so the potential energy U (it's best to avoid the letter E since that's usually used to stand for the electric field) is
[tex]U_i = \frac{kq(-q)}{R} = -\frac{kq^2}{R}[/tex]
Now when the distance between them increases to 3/2 R, the potential energy is now
[tex]U_f = \frac{kq(-q)}{3R/2} = -\frac{2}{3} \frac{kq^2}{R}[/tex]
So now you want to figure out for part (a), is Ui>Uf or Ui<Uf. Note that you don't need to know specific values for q and R because both Ui and Uf are proportional to the same quantity, but you should consider whether the potential energies are positive or negative because it'll affect your answer.
Once you think you have an answer, you should consider whether it's reasonable or not. The balls are oppositely charged, so they're attracted to each other. Would you have to do additional work to separate them? Does that jibe with how you think the potential energy changes?