Electric field at point p if p is on a bisector between two opposite charges

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SUMMARY

The discussion focuses on calculating the electric field at point P, located on the perpendicular bisector between two opposite charges separated by a distance of 2a. The relevant equation for the electric field is e = (kQ)/(r^2), where k is Coulomb's constant (8.99 x 10^9 N m²/C²). The participants suggest using the Pythagorean theorem to simplify the calculation instead of relying on trigonometric functions. The final expression for the electric field should be articulated in terms of Q, x, a, and k.

PREREQUISITES
  • Understanding of electric fields and Coulomb's law
  • Familiarity with the concept of point charges
  • Knowledge of trigonometric functions and their applications in physics
  • Proficiency in using the Pythagorean theorem for geometric problems
NEXT STEPS
  • Study the derivation of electric fields from point charges using Coulomb's law
  • Learn how to apply the Pythagorean theorem in electrostatics problems
  • Explore the concept of superposition of electric fields from multiple charges
  • Investigate the implications of electric field direction and magnitude in different configurations
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Students studying electromagnetism, physics educators, and anyone interested in understanding electric field calculations in electrostatics.

zyphriss2
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Homework Statement


Determine magnitude of the electric field at the point P. The two charges are separated by a distance of 2a. Point P is on the perpendicular bisector of the line joining the charges, a distance x from the midpoint between them. Express your answer in terms of Q, x, a, and k.


Homework Equations


e=(kq)/(r^2)



The Attempt at a Solution


Top e=((8.99x10^9)*Q)/(tan^-1(a/x))
Bottom e=((8.99x10^9)*Q)/(tan^-1(a/x))

I just don't know how to determine the magnitude, and express my answer in terms of the given variables...i do know that the answer is in terms of q
 
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Hi zyphriss2! :smile:
zyphriss2 said:

The Attempt at a Solution


Top e=((8.99x10^9)*Q)/(tan^-1(a/x))
Bottom e=((8.99x10^9)*Q)/(tan^-1(a/x))

oooh … why so trigonmetric? :cry:

just use Pythagoras! :smile:
 

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