A single conservative force F = (4.0x - 13)i N, where x is in meters, acts on a particle moving along an x axis. The potential energy U associated with this force is assigned a value of 26 J at x = 0. (a) What is the maximum positive potential energy? At what (b) negative value and (c) positive value of x is the potential energy equal to zero?
Force = dU/dx where U is the potential energy.
The Attempt at a Solution
Okay, so we find the anti-derivative of the given force then we have: U = x^2/2 - 13x. Then what? At x = 0 m, U is 26 J. At the maximum U, we know the kinetic energy is 0 (v = 0).