Potential Energy Q: 1000kg Cart on Hill, Kinetic/PE/Velocity?

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SUMMARY

The discussion centers on calculating the potential energy (PE) and kinetic energy (KE) of a 1000kg cart rolling down an 80m hill. At the top of the hill, the potential energy is 800,000J, with zero kinetic energy and a height of 80m. As the cart descends to a smaller hill with a velocity of 20m/s, its kinetic energy is calculated to be 200,000J. The conservation of energy principle is applied to derive the height of the smaller hill using the equation mgh1 = mgh2 + 1/2mv^2.

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  • Understanding of gravitational potential energy (PE = mgh)
  • Knowledge of kinetic energy (KE = 1/2mv^2)
  • Familiarity with the conservation of energy principle
  • Basic algebra for solving equations
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Question: There is a 1000kg cart on the top of 80m hill which it rolls down onto a smaller hill of unknown height with a velocity of 20m/s. What is potential energy and height of its current position? What is the kinetic energy, potential energy, and velocity when it reaches a flat surface? Assume no losses to friction and with a g of 10m/s. Thanks a lot
 
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So far I have the four answers for when they are at the top of the 80m hill before moving. K.E.=0 P.E.= 800000J, V=0, H=80m. I've calculated their kinetic energy to be 200000J at the smaller hill with the information provided(v=20m/s) I would appreciate it if someone could tell me how to go about doing this question.
 
energy is conserved So

(top) mgh1 = mgh2 + 1/2mv^2 (smaller hill)

you know everything but "h2", use algebra to find "h2"
 

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