- #1

muna580

I am doing my homewrok which relates to Work/Engery/Power stuff. Well, I came along this question and I didn't understand how to do it. I went to my book, and the book had the exact example of this problem. The book said to take the derivitive of this function and set it equal to 0 and solve for x. I did that and put in the answern and I got the answr right.

As a good student, wanting to learn and understand phsyics, I wanted to undertand why I would take the derivitive of this function and set it equal to 0. Can someone please explain to me, but I don't really undertand how to do this problem.

So far, I know the following things

[tex] \Sigma W = - \Delta U [/tex]

[tex] \Sigma W = \Delta K [/tex]

[tex] \Delta K = \frac{1}{2}mv^2 - \frac{1}{2}mvo^2 [/tex]

http://img156.imageshack.us/img156/2515/untitled1zn0.jpg

As a good student, wanting to learn and understand phsyics, I wanted to undertand why I would take the derivitive of this function and set it equal to 0. Can someone please explain to me, but I don't really undertand how to do this problem.

So far, I know the following things

[tex] \Sigma W = - \Delta U [/tex]

[tex] \Sigma W = \Delta K [/tex]

[tex] \Delta K = \frac{1}{2}mv^2 - \frac{1}{2}mvo^2 [/tex]

http://img156.imageshack.us/img156/2515/untitled1zn0.jpg

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