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Pottery wheel, angular acceleration, and required speed

  1. Oct 16, 2012 #1
    1. The problem statement, all variables and given/known data

    a small rubber wheel is used to drive a large pottery wheel, and they are mounted so that they touch. if the small wheel has a radius of 2.01 cm and accelerates at a rate of 7.08 rad/s^2 and is in contact with the pottery wheel (24.2 cm) without slipping, find the angular acceleration of the pottery wheel and find the time it takes it to reach 67.4 rpm?

    2. Relevant equations

    w=w0+at

    3. The attempt at a solution

    I've already found the acceleration of the pottery wheel to be 0.588 rad/s^2 but I'm having trouble with the 2nd part

    r1=0.0201 m
    r2=0.242 m
    alpha1=7.08 rad/s^2
    alpha2=0.588 rad/s^2

    w2 = 67.4 rpm -> 3.53 rad/s

    w=w0+at
    3.53=0+(0.588)t
    t=6.003 s

    what am I doing wrong?
    1. The problem statement, all variables and given/known data



    2. Relevant equations



    3. The attempt at a solution
     
  2. jcsd
  3. Oct 16, 2012 #2

    tiny-tim

    User Avatar
    Science Advisor
    Homework Helper

    Hi SereneKi! :smile:
    nooo :redface: … one revolution = two π :wink:
     
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