Power associated with net force

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The discussion focuses on proving that the power associated with net force is the rate of change of kinetic energy, expressed as P*F_net = dK/dt. Initial attempts involved using the definitions of power and work, leading to confusion over dimensional correctness. Clarification revealed that F_net was intended as a subscript for power, not a product, aligning the equation correctly. The conclusion suggests that with this understanding, the solution is nearly complete. The thread emphasizes the importance of correctly interpreting symbols in physics equations.
REVIANNA
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Homework Statement



How to prove :
[/B]
##P*F_net=((dK)/(dt))##
i.e. power associated with the net force is the rate of change of kinetic energy.

The Attempt at a Solution


[/B]
if I use the definition of power ans then that of work I get (m*a*ΔS )*(F_net)
further using F_net=ma
LHS= ##m^2*a^2*ΔS##

There is no question along with it for which I could have though about the system and forces.
so I am assuming const force and acceleration.
 
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REVIANNA said:
P∗Fnet=((dK)/(dt))P*F_net=((dK)/(dt))
Is that product of force and power on LHS? If yes, the equation looks dimensionally incorrect.
Actually, if you solved dK/dt first, you'll get power.
 
Last edited:
cnh1995 said:
Is that product of force and power on LHS? If yes, the equation looks dimensionally incorrect.
Actually, if you solved dK/dt first, you'll get power.

so sorry ,actually the F_net was written as the subscript P ,not their product
this makes complete sense now
##P_F=(dK/dt)##
 
REVIANNA said:
so sorry ,actually the F_net was written as the subscript P which not their product
this makes complete sense now
##P_F=(dK/dt)##
Then I believe answer is a couple of steps away. Good luck..
 
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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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