Power Developed for Conveyor Belt Transporting Newspapers

[Lothar]

Homework Statement

A 13.5 m long conveyor belt, inclined at 30.0°, is used to transport bundles of newspapers from the mailroom up to the cargo bay to be loaded on to delivery trucks. Each newspaper has a mass of 1.0 kg, and there are 26 newspapers per bundle. Determine the power that the conveyor develops if it delivers 15 bundles per minute.

Homework Equations

w = fd
w = fdcos(theta)
P = w/t

The Attempt at a Solution

I've tried several things getting incorrect answers of:
57.33
859.95
744.74
49.6
372.4

 

[LowlyPion]

Homework Statement

A 13.5 m long conveyor belt, inclined at 30.0°, is used to transport bundles of newspapers from the mailroom up to the cargo bay to be loaded on to delivery trucks. Each newspaper has a mass of 1.0 kg, and there are 26 newspapers per bundle. Determine the power that the conveyor develops if it delivers 15 bundles per minute.

Homework Equations

w = fd
w = fdcos(theta)
P = w/t

The Attempt at a Solution

I've tried several things getting incorrect answers of:
57.33
859.95
744.74
49.6
372.4

Welcome to PF.

Maybe focus on your last equation? If you figure the work performed in 1 minute you're just about home free right?

So what is the work of moving 1 newspaper to the top of the ramp?

W = ΔPE = m*g*Δh

where Δh = 13.8*sin30 = 1/2*13.8 = 7.9 m

Figure then the total work from 15*26 newspapers and that tells you how much for a minute, so getting to work/sec is really easy then.