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Homework Help: Power distribution - Per unit question problem

  1. Dec 15, 2011 #1
    Hi,

    exam question:
    23vl0tg.jpg

    My doubts start where it comes up with: S=75(0.8-j0.6) and Vr = 0.97 p.u.

    Its easy to determine that 75 comes from 60/0.8, but where is the part in the brackets coming from ?

    Also how was the 0.97 determined ?

    Thanks in advance.
     
  2. jcsd
  3. Dec 18, 2011 #2

    jim hardy

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    Science Advisor
    Gold Member

    does not PF of 0.8 dictate a 3::4::5 triangle? (0.6::0.8::1.0) ? that's the bracketed part.

    and 32/33 = .97?

    remember it's per unit - everything a fraction of nominal.
     
  4. Dec 19, 2011 #3
    This must be way he did it, Thanks.
     
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