Power distribution - Per unit question problem

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SUMMARY

The discussion focuses on understanding the per unit system in power distribution, specifically analyzing the complex power S=75(0.8-j0.6) and the reference voltage Vr=0.97 p.u. The value 75 is derived from the formula 60/0.8, while the bracketed components represent the power factor of 0.8, which corresponds to a 3:4:5 triangle in phasor representation. The value of 0.97 is calculated as the ratio of 32 to 33, emphasizing the per unit methodology where all values are expressed as fractions of nominal values.

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JJ91
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Hi,

exam question:
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My doubts start where it comes up with: S=75(0.8-j0.6) and Vr = 0.97 p.u.

Its easy to determine that 75 comes from 60/0.8, but where is the part in the brackets coming from ?

Also how was the 0.97 determined ?

Thanks in advance.
 
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does not PF of 0.8 dictate a 3::4::5 triangle? (0.6::0.8::1.0) ? that's the bracketed part.

and 32/33 = .97?

remember it's per unit - everything a fraction of nominal.
 
This must be way he did it, Thanks.
 

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