1. The problem statement, all variables and given/known data 65 kW is to arrive at a town over two 0.100 ohm lines. Estimate how much power is saved if the voltage is stepped up from 120 V to 1200 V and then down again, rather than simply transmitting at 120V. 2. The attempt at a solution First I want to find the power lost in each line. Since the power is delivered over two lines, the power over each line is half of the total. P = VI 65000/2 = 120I I = 271 A So for the total power lost in the two lines, P = (I^2)*R*2 P = 14670 W Now I want to find the power lost if the voltage is 1200V. The same procedures apply. 65*10^3/2 = 1200I I = 27.1 A P = (I^2)R*2 P = 146.7 W Difference between the two values of "wasted" power = 14500 W That's my answer. But the textbook gave me an answer of around 54000 W. I looked at its steps. I don't know if they are wrong. The book first finds the delivered current by the equation 65000 W = 120 I Then it finds the power wasted by the 2(I^2)R. Is that double counting?