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## Homework Statement

Determine the heat loss in the circuit that is connected in series with two batteries (12 V and 6V) and two resistors (6ohms and 4 ohms).

## Homework Equations

## The Attempt at a Solution

I used the difference in P = V^2/R, the power dissipated in the circuit, to calculate the heat loss.

Heat energy loss/t = (12^2/6) - (6^2/4) = 15W.

Apparently, I am incorrect; but I don't know the right direction to solve this problem.

Thanks in advance for your guidance/help.