Power of an Engine: Work & Effects

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SUMMARY

The discussion centers on calculating the work and power output of an engine during a circuit process. The work performed by the engine in one revolution is established as 1.6 kJ, derived from the area within the square circuit. The power output, initially miscalculated, is correctly determined to be 8,000 W when using the formula P = W/t, where W is 1.6 kJ and t is 0.2 s. The correction emphasizes that power is the rate at which work is done, necessitating division rather than multiplication.

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Homework Statement


An engine goes through a "square" circuit process (is btw "circuit process" this the correct term in English?) according to the diagram below:
attachment.php?attachmentid=73010&stc=1&d=1410425307.png


a) How much work is performed by the engine during one revolution in the circuit process?
b) What effect does the engine deliver if it takes 0.2 s for the circuit process to go through one revolution?

Homework Equations


W = p*V
P = W*t

The Attempt at a Solution


For a) we have simply the area within the square, which is 1.6 kJ.

For b) if we have W = 1.6 kJ and t = 0.2 s, then we should get P = 1.600 J * 0.2 s = 320 W. Why is this not correct?
 

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You should divide, not multiply - power is the rate at which work is done by the engine.
 
Ah yes, of course. :redface: Thanks.
 

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