Power produced from alpha decay

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SUMMARY

The discussion focuses on calculating the electrical power produced from a 14 kg sample of 240Pu through its alpha decay, with a device efficiency of 60%. The energy released per decay (Q) is determined to be 5.25572 MeV. To find the total power output in watts, participants must calculate the number of decaying plutonium atoms per second and multiply this by the energy released per decay, adjusted for efficiency. The expected power output is 59.4 watts.

PREREQUISITES
  • Understanding of alpha decay and nuclear reactions
  • Knowledge of energy conversion from MeV to Joules
  • Familiarity with Avogadro's number and its application in atomic calculations
  • Basic principles of efficiency in energy conversion
NEXT STEPS
  • Calculate the decay rate of Pu-240 using its half-life of 6560 years
  • Learn about energy conversion factors, specifically from MeV to Joules
  • Explore the concept of radioactive decay and its applications in power generation
  • Investigate the efficiency of different nuclear power generation methods
USEFUL FOR

This discussion is beneficial for physics students, nuclear engineers, and anyone interested in the principles of nuclear power generation and energy calculations from radioactive materials.

MattHorbacz
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Homework Statement


Assume that a 14 kg sample of 240Pu is used to produce electrical power from its α decay. If your device is 60% efficient in producing electrical power, how much power can be produced? (in watts)

Homework Equations


Q=mass of plutonium-mass alpha-mass daughter; 240 plutonium= alpha +uranium236

The Attempt at a Solution


I found Q to be 5.25572 Mev. The number of Plutonium atoms is 14*10^3 grams * 6.022*10^23/240. Multiply this by Q to get total energy in ev. Then multiply by 1.602176565e-19 to get in terms of Joules. Then multiply by .6, and that's where I get stuck. No idea how to get to watts. the answer should be 59.4 watts.
 
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MattHorbacz said:

Homework Statement


Assume that a 14 kg sample of 240Pu is used to produce electrical power from its α decay. If your device is 60% efficient in producing electrical power, how much power can be produced? (in watts)

Homework Equations


Q=mass of plutonium-mass alpha-mass daughter; 240 plutonium= alpha +uranium236

The Attempt at a Solution


I found Q to be 5.25572 Mev. The number of Plutonium atoms is 14*10^3 grams * 6.022*10^23/240. Multiply this by Q to get total energy in ev. Then multiply by 1.602176565e-19 to get in terms of Joules. Then multiply by .6, and that's where I get stuck. No idea how to get to watts. the answer should be 59.4 watts.

You need to know how quickly Pu-240 decays. Do you know the half-life of Pu-240?
 
I looked it up at it seems to be about 6560 years
 
MattHorbacz said:
I looked it up at it seems to be about 6560 years
OK, from that, you need to figure out how many atoms of Pu-240 are decaying each second in your original 14 kg of this substance.

Knowing that, you have already computed how much energy is released with each decay, so finding the power should be trivial.
 
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