Power requirement to turn blade in free air

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SUMMARY

The discussion centers on calculating the power required to turn a wood impeller with four flat blades in free air, specifically using equations derived from kinetic energy principles. Key equations include KE=1/2mv² for kinetic energy and Power=1/2 (P/RairT)(π(D²-d²)/4)v³ for power calculations, where P is atmospheric pressure, T is ambient temperature, and R is the specific gas constant of air. Participants emphasize the importance of conducting tests safely, recommending the use of a housing to contain potential splinters and prevent accidents. The conversation highlights the necessity of understanding engineering principles, particularly stress and fatigue in rotating mechanisms.

PREREQUISITES
  • Understanding of kinetic energy equations (KE=1/2mv²)
  • Familiarity with fluid dynamics concepts, specifically flow rate and density calculations
  • Knowledge of atmospheric pressure and temperature effects on air density
  • Basic principles of mechanical engineering, particularly stress and fatigue analysis
NEXT STEPS
  • Research "Kinetic Energy and Power Calculations for Rotating Machinery"
  • Study "Fluid Dynamics and Airflow in Impellers"
  • Learn about "Engineering Strength of Materials" focusing on stress and fatigue
  • Explore "Safe Testing Protocols for Rotating Equipment"
USEFUL FOR

Mechanical engineers, hobbyists building impellers, and individuals interested in safe testing methods for rotating machinery will benefit from this discussion.

aarothepharo
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Does anybody have any equations that predict the power required to turn an impeller in free air? I am building a wood impeller four blades flat in reference to rotation radiating from central hub. I need to predict the length of the blade to be able match a certain HP.
 
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You may start with Kinetic energy (KE=1/2mv2) of the wind which would pass through the projected circular area of your blade.
Say area on the blade is A = π(D2-d2)/4

Flow rate of wind passing through that projection is Q = Av (m3/sec) & ρ = m'/Q.
Combining these equations will give you something like this:

KE rate = 1/2 ρQv2 = 1/2 ρ(π(D2-d2)/4)v3 (Power J/s) This is the available energy rate that can be utilize at certain wind speed passing through an annulus.

You could also express ρ = P/RairT, so you have something like
Power=1/2 (P/RairT)(π(D2-d2)/4)v3
where: P- Atmospheric Pressure;
T -ambient temperature;
R-specific gas constant of air
v - wind speed
 
Last edited:
You can find a lot of this in Marks Mechanical Engineering Handbook under Windmills.
 
aarothepharo said:
I am building a wood impeller four blades flat in reference to rotation radiating from central hub.
So this is an impeller, not a propeller or turbine.
As the impeller rotates, air circulates from the inside to the outside.
The mass of air, m, in kg that moves must be accelerated to a velocity, v, in metres per second, sufficient to depart the impeller.
Energy is 0.5 * mass * v2. Power is energy in joules per unit time in seconds.
 
Baluncore. I'm building an impeller in a housing however I want to spin it in free air off of a 6.5 HP engine to test if it can spin fast enough without shattering.
 
aarothepharo said:
I'm building an impeller in a housing however I want to spin it in free air off of a 6.5 HP engine to test if it can spin fast enough without shattering.
If the impeller is in a housing it will consume less power than if spinning in free air at the same RPM.
It is safer to test it in a housing because that housing may contain some of the splinters.
Do not test it without a housing capable of containing all the fragments.
 
Baluncore said:
If the impeller is in a housing it will consume less power than if spinning in free air at the same RPM.
It is safer to test it in a housing because that housing may contain some of the splinters.
Do not test it without a housing capable of containing all the fragments.
Sounds unsafe to me testing with very little knowledge about a rotating mechanism which could end up in a fatality and destruction both property and life.
I strongly recommend not to test at all.
Do not deal with things you are not well equipped and able to do. Invest more in knowledge first and education, other than doing testing, a "destructive testing" most probably, when it involves " i guess it will work".
 
aarothepharo said:
Baluncore. I'm building an impeller in a housing however I want to spin it in free air off of a 6.5 HP engine to test if it can spin fast enough without shattering.
Your thread does not fit any more to the topic. I suggest you read and study Engineering Strength of Materials, specifically about "stress and/or fatigue" on a rotating disc or propeller.
 
Baluncore said:
If the impeller is in a housing it will consume less power than if spinning in free air at the same RPM.
It is safer to test it in a housing because that housing may contain some of the splinters.
Do not test it without a housing capable of containing all the fragments.
I agree.
 
  • #10
Legolaz said:
Sounds unsafe to me testing with very little knowledge about a rotating mechanism which could end up in a fatality and destruction both property and life.
I strongly recommend not to test at all.
Do not deal with things you are not well equipped and able to do. Invest more in knowledge first and education, other than doing testing, a "destructive testing" most probably, when it involves " i guess it will work".
Legolaz: I am a Mechanical Engineer. I have found a lot of formulas and probably could use calculus but was wonder if anyone knew of a formula to prevent me from doing it.

Any test can be conducted safely and any test that can not be conducted safely should not be conducted. I abide by those rules.
 
  • #11
Legolaz said:
Your thread does not fit any more to the topic. I suggest you read and study Engineering Strength of Materials, specifically about "stress and/or fatigue" on a rotating disc or propeller.
Legolaz: I understand your concern and have already studied the design with a strength stand point. Thanks for the feed back.
 
  • #12
It looks like nobody has a formula for me so I will use calculus. Thanks for all the help everone
 

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