Power Series Representation of (1+x)/(1-x)

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Homework Help Overview

The discussion revolves around finding the power series representation of the function f(x) = (1 + x) / (1 - x). Participants are exploring the derivation of the series and the significance of the additional term in the representation.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the use of long division to isolate terms in the function and question the origin of the additional 1 in the power series representation. There is also mention of changing the index of summation to facilitate understanding.

Discussion Status

The discussion is active, with participants providing insights into the use of long division and index manipulation. Some guidance has been offered regarding the interpretation of summation indices and the significance of the term x^0 = 1.

Contextual Notes

Participants are navigating the complexities of power series and the manipulation of summation indices, indicating a need for clarity on these concepts. There is no consensus yet on the complete understanding of the problem.

Desharnais
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Homework Statement



For the power series representation of, f(x)=1+x1−x which is 1+2∑from n=1 to inf (x^n), Where does the added 1 in front come from? How do I get to this answer from ∑n=0 to inf (x^n)+∑n=0 to inf (x^(n+1))

Homework Equations


The Attempt at a Solution



I arrived at ∑n=0 to inf x^n + ∑ n=0 to inf x^(n+1)
 
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The 1 in front comes from using long division to isolate the 1/(1-x) term. I'm not sure what you're asking in your second question though. If you want to change the index of a summation, you can do it entirely artificially. Namely, if you want \sum_{n=1}^\infty x^n to look like a sum where the lower index starts at 0 instead of 1, define a new index k = n-1.
 
##x^0=1##
 
Rereading your question, I now understand what you are saying. Have you been doing as suggested? Use long division to break up the rational function, then use vela's comment about how x^0 = 1 and you'll get the answer your originally posted.
 

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