Power, the rate of energy transfer

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Homework Help Overview

The problem involves a forklift lifting a 613.0 kg mass with a power output of 950 W. Participants are exploring the relationship between power, work, and velocity in this context.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants express uncertainty about the available information, particularly the lack of time and distance. They discuss the equations for power and work, questioning how to relate force and velocity.

Discussion Status

There is ongoing exploration of the relationships between power, work, and force. Some participants are attempting to derive equations and clarify concepts, while others are struggling with the application of these ideas. No consensus has been reached, and multiple interpretations are being considered.

Contextual Notes

Participants note the absence of time and distance in the problem setup, which complicates their ability to find velocity. There is also mention of the need for clarity on the definitions of work and force.

dbigtheory
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Homework Statement


A 613.0 kg mass is placed on a forklift that can generate 950 W of power. What is the constant speed of the forklift while lifting this load?


Homework Equations


P= E/T
e=energy in joules
T= time

The Attempt at a Solution


not enough information therefore i couldn't do it. pls help
 
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dbigtheory said:

Homework Statement


A 613.0 kg mass is placed on a forklift that can generate 950 W of power. What is the constant speed of the forklift while lifting this load?


Homework Equations


P= E/T
e=energy in joules
T= time

The Attempt at a Solution


not enough information therefore i couldn't do it. pls help

Hint: P = \frac{dW}{dt}

Where W is the work.
 
time and work are not given, only have Watt and i have no idea wat to do with Kg and i need to find velocity...dunno
 
dbigtheory said:
time and work are not given, only have Watt and i have no idea wat to do with Kg and i need to find velocity...dunno

What is the equation for the work done in this problem?
 
W= FD but i don't have the distance
 
dbigtheory said:
W= FD but i don't have the distance

Right, and what is F?
 
Watt, power
 
No, F is the force doing the work W = FD, what force is doing the work?
 
i know what you're getting into but i have try that attempt before, even so I don't understand how to find the velocity with FG
 
  • #10
I'm trying to help you lol. If you knew what I was getting at you would already have the answer. You know what W is so what is dW/dt?
 
  • #11
velocity but i don't have the time?
 
  • #12
Would you please show your work. I cannot help you otherwise. Show what you have done. W is work not velocity.
 
  • #13
ok i think i get it you divide the FG by the power to find time and then divide the Fg by the time>? i think
 
  • #14
dbigtheory said:
ok i think i get it you divide the FG by the power to find time and then divide the Fg by the time>? i think

UGH. PLEASE WRITE EQUATIONS. Let's start over, this is not that difficult you can do it I promise, but I don't want to just give you the answer. You know derivatives right?

P = \frac{dW}{dt}

Where W is the work done. So power is the rate of change of work with respect to time. So if you can write out the equation for work then all you have to do is take the derivative of it (dw/dt) and that will be equal to the power.
 
  • #15
so 950w= 6007N/dt and then i use it to find time and i know velocity?
 
  • #16
dbigtheory said:
so 950w= 6007N/dt and then i use it to find time and i know velocity?

W = F_g x = mgx

What is dW/dt?
 
  • #17
velocity, i got 950m/s. i got the time by dividing dw by P. i think tis should be right
 
  • #18
yo man don't worry i about it. i screwed up, the answer suppose to be 0. 158m/s. thanks for your help though
 
  • #19
dbigtheory said:
velocity, i got 950m/s. i got the time by dividing dw by P. i think tis should be right

That is 2000 mph! DO YOU KNOW DERIVATIVES?? This is what you are going to do:

FIND dw/dt (W = mgx) where x is the change in height and POST WHAT YOU GET FOR THE DERIVATIVE.
 
  • #20
Remember mg is a constant, but x is not.
 
  • #21
Grazie!
 
  • #22
No problem
 

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