the question states at 120 kg tractor goes up a 21 degree incline of 12.0 m in 2.5 seconds. what is the power? ok i know power is W/T which is basically Fd/T my question is how do you use the incline. work is Fdcos0 but i just dont see why its cosine in this question. the work is going UP so shouldnt you want to use the vertical component? meaning use sine insteand of cosine? doesnt make sense to me. a similar question is a 185 fridge goes up 10.0 m at an angle of 11 degrees, what is the work done? again, its going up so should we use cosine or sine? i think it should be sine but the equation says use cosine. dont quite get it. please help. thanks.