Friction on an incline and velocity

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Homework Help Overview

The problem involves a block sliding up an incline with an initial velocity, where friction is present. The incline angle is given, along with the coefficient of kinetic friction. The objective is to determine how far the block travels along the incline before coming to a stop.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the energy transformations involved, noting the initial kinetic energy and the potential energy at the height reached on the incline. There is an emphasis on the role of friction as an external force affecting the motion.

Discussion Status

Some participants are exploring the relationship between kinetic energy and gravitational potential energy, while others are questioning the appropriate equations to use in the context of work and energy. There is a collaborative effort to clarify concepts without reaching a definitive solution.

Contextual Notes

Participants express uncertainty regarding the necessary parameters and equations, indicating a lack of complete information about the mass and acceleration. The discussion reflects the constraints of a homework setting, where direct solutions are not provided.

df102015
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Homework Statement


A block is sliding with an initial velocity of 7.3 m/s along a frictionless horizontal surface when it then goes up an incline of 51.5 degrees that does have friction. If the kinetic friction coefficient is 0.1 then how far along the incline (hypotenuse) will the object travel before it stops?
7-p-044.gif


Θ = 51.5°
µ(k) = 0.1
v(initial) = 7.3 m/s
v(final) = 0 ...because the question asks at what point will it stop, meaning there is no more speed.
g = 9.81
d = ?
m = ?
a = ? ...i do not know if i even need acceleration
F = ?
W = ?

Homework Equations


KE = W = 1/2mv(final) - 1/2mv(initial)
F = mg
W = Fd
Force up ramp... F = mg sinΘ
Normal Force against ramp... Fnormal = mg cosΘ
Force of friction between block and ramp... F(f) = µ Fnormal

The Attempt at a Solution


Honestly i have no clue where to even begin, i am so lost on this problem :(
Also, my equations could be wrong.
 
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Okay, Let's think about it together alright?

At the horizontal surface, There is no friction. So there is no change in kinetic energy Which mean there is no change in the total energy
But on the incline, I have an external force acting on it which is friction of course.
and work is W = f*d cos theta.
What does work do? if the work is positive then it adds energy to the object. If it is negative then it takes away energy.

Now think of the initial position and the final position, What kind of energy does the object have at these moments?

Hint: at the end of the movement, The velocity is zero and it is not at the ground level so there is height (What form of energy is that?)

Put it in an equation describing what happens to the total energy and volaaa you have solved it!
 
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Biker said:
Okay, Let's think about it together alright?

At the horizontal surface, There is no friction. So there is no change in kinetic energy Which mean there is no change in the total energy
But on the incline, I have an external force acting on it which is friction of course.
and work is W = f*d cos theta.
What does work do? if the work is positive then it adds energy to the object. If it is negative then it takes away energy.

Now think of the initial position and the final position, What kind of energy does the object have at these moments?

Hint: at the end of the movement, The velocity is zero and it is not at the ground level so there is height (What form of energy is that?)

Put it in an equation describing what happens to the total energy and volaaa you have solved it!

Okay i think i get what you're saying, so it starts with kinetic energy and ends with gravitational potential energy. But what equations, i don't know which ones i could use...
 
Well I know that
W = E2- E1
Substitute these values with what you have.
For example E1 should be kinetic energy.
 
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