Practice test help - probability from data

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    Data Probability Test
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SUMMARY

The discussion focuses on calculating probabilities related to orthopedic surgeries, specifically knee replacements. The correct answer for the probability of an orthopedic surgical case involving knee surgery is established at 26%. For individuals aged 18-44 who undergo knee surgery, the probability of having a full knee replacement is approximately 18%, calculated using the formula for probability: the number of occurrences divided by the total number of occurrences. The conversation emphasizes the importance of understanding the total number within specific categories when calculating these probabilities.

PREREQUISITES
  • Understanding of basic probability concepts
  • Familiarity with orthopedic surgery statistics
  • Ability to interpret data tables
  • Knowledge of probability formulas
NEXT STEPS
  • Study the concept of conditional probability in depth
  • Learn how to analyze data using statistical software like R or Python
  • Explore the implications of age demographics on surgical outcomes
  • Research the American Academy of Orthopedic Surgeons' data collection methods
USEFUL FOR

Students in statistics, healthcare professionals involved in orthopedic surgery, and anyone interested in understanding the application of probability in medical data analysis.

CosmoK123456
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Having some trouble with this. I think the answer to question 1 is 26% and question 2 is 2%. I'm not sure when to divide by 163 or 100??
practice test help:
About 26% of orthopedic surgeries involves knee problems. The following table summarizes data collected from a sample of adults who have knee surgery. (Source: American Academy of Orthopedic Surgeons)

age, full knee replacement, no knee replacement
18-44,2, 9
45-64,25, 11
65-74,43,27
75-84, 27, 14
85-older,3, 2 1) What is the probability that an orthopedic surgical case selected at random involves
knee surgery?

2) What is the probability that a person from ages 18 – 44 who has knee surgery has a
full knee replacement?

3) What is the probability that a person from 45 – 64 who has knee surgery has a full
knee replacement?

4) What is the probability that a person who has knee surgery has a full knee
replacement?
 
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Welcome to MHB, CosmoK! :)

CosmoK123456 said:
Having some trouble with this. I think the answer to question 1 is 26% and question 2 is 2%. I'm not sure when to divide by 163 or 100??
practice test help:
About 26% of orthopedic surgeries involves knee problems. The following table summarizes data collected from a sample of adults who have knee surgery. (Source: American Academy of Orthopedic Surgeons)


[TD="align: center"]age[/TD]
[TD="align: center"]full knee replacement[/TD]
[TD="align: center"]no knee replacement[/TD]

[TD="align: center"]18-44[/TD]
[TD="align: center"]2[/TD]
[TD="align: center"]9[/TD]

[TD="align: center"]45-64[/TD]
[TD="align: center"]25[/TD]
[TD="align: center"]11[/TD]

[TD="align: center"]65-74[/TD]
[TD="align: center"]43[/TD]
[TD="align: center"]27[/TD]

[TD="align: center"]75-84[/TD]
[TD="align: center"]27[/TD]
[TD="align: center"]14[/TD]

[TD="align: center"]85-older[/TD]
[TD="align: center"]3[/TD]
[TD="align: center"]2[/TD]

1) What is the probability that an orthopedic surgical case selected at random involves
knee surgery?

2) What is the probability that a person from ages 18 – 44 who has knee surgery has a
full knee replacement?

3) What is the probability that a person from 45 – 64 who has knee surgery has a full
knee replacement?

4) What is the probability that a person who has knee surgery has a full knee
replacement?

You have question 1 correct.

For question 2 and following, you need to know that the probability that something occurs, is the number of occurrences divided by the total number of occurrences.
In a formula:
$$\text{probability on event} = \frac{\text{number of occurrences of event}}{\text{total number of occurrences}}$$
The catch is that in your case the total number is the total number within a certain category.

Applied to question 2, you have:
\begin{aligned}
P &= \frac{\text{number of persons from ages 18 – 44 who have knee surgery who also have a
full knee replacement}}{\text{total number of persons from ages 18 – 44 who have knee surgery}} \\
&= \frac{2}{2 + 9} \\
&= \frac{2}{11} \\
&\approx 18\%
\end{aligned}

Perhaps you can apply it to questions 3 and 4?

EDIT: Fixed to 18% as Prove It remarked.
 
Last edited:
I like Serena said:
Welcome to MHB, CosmoK! :)
You have question 1 correct.

For question 2 and following, you need to know that the probability that something occurs, is the number of occurrences divided by the total number of occurrences.
In a formula:
$$\text{probability on event} = \frac{\text{number of occurrences of event}}{\text{total number of occurrences}}$$
The catch is that in your case the total number is the total number within a certain category.

Applied to question 2, you have:
\begin{aligned}
P &= \frac{\text{number of persons from ages 18 – 44 who have knee surgery who also have a
full knee replacement}}{\text{total number of persons from ages 18 – 44 who have knee surgery}} \\
&= \frac{2}{2 + 9} \\
&= \frac{2}{11} \\
&\approx 22\%
\end{aligned}

Perhaps you can apply it to questions 3 and 4?

\displaystyle \frac{2}{11} \approx 18\%, not 22%...
 

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