Pre-calculus homework help

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Samanthalovesmath
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Graph of a downward-opening parabola on x and y axes, with labeled points (-4, 4) at the vertex and (0, -12) on the y-axis; axis ticks at -10 and 10 on x, 22 and -22 on y, beside the prompt to determine the quadratic function.
 
It's easy, let's suppose the quadratic is $ax^2 +bx +c = 0$ From the graph we can say $c= -12$ and if you know that the vertex is given by ( $-b \over 2a$ , $-D \over 4a$ )
Put the values you will get the answer.