Precession of relativistic orbit in pure inverse-square force

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SUMMARY

The discussion focuses on the prediction of precession in relativistic orbits under a pure inverse-square force, specifically demonstrating that Special Relativity predicts a precession of π(GMm/cl)² radians per orbit. The problem is framed using differential equations for Newtonian orbits, transitioning to relativistic equations by substituting mk with ϒmk, where ϒ is the Lorentz factor. The equations derived include d²u/dθ² + (1 - k²/c²l²)u = Ek/c²l², leading to the conclusion that the precession can be calculated using the phase angle change Δθ - Δθ' = 2π(1/ω - 1).

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  • Understanding of Special Relativity and Lorentz transformations
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RylonMcknz
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PROBLEM:
Show that Special Relativity predicts a precession of π(GMm/cl)2 radians per orbit for any elliptic orbit under a pure inverse-square force.

where G is gravitational constant, M is mass of larger body, m is mass of smaller orbiting body, c is speed of light and l is angular momentum.​

HINTS:
Differential equation for Newtonian inverse-square force orbit: d2u/dθ2 + u = mk/l2 (Eq.1), where u = 1/r, k = GMm.

To make this relativistic: mk→ϒmk, where ϒ = 1/√(1 - (v2/c2)).

Also E = ϒmc2 + U.

Then right side of (Eq. 1) becomes ⇒ϒmk/l2 = (E - U)k/c2l2 = (E + ku)k/c2l2 (Eq. 2).

Precession causes the following change of phase angle (in radians/orbit):

Δθ - Δθ' = 2π/ω - 2π = 2π(1/ω - 1) (Eq. 3).​

ATTEMPT:
(Eq. 1) & (Eq. 2) d2u/dθ2 + u = (E + ku)k/c2l2

d2u/dθ2 + u - k2u/c2l2 =
Ek/c2l2

⇒ d2u/dθ2 + (1 - k2/c2l2)u = Ek/c2l2
,

where ω2 = (1 - k2/c2l2) (Eq. 4),
and let A = Ek/c2l2.

Then substitute y = u - A/ω2.

Then we have d2y/dθ2 + ω2[y + A/ω2] - A = 0

d2y/dθ2 + ω2y = 0

Solution is then y = y0cos(ωθ - θ0).

I then try substituting (Eq. 4) into (Eq. 3) to find the resulting precession in radians per orbit, but this doesn't not give the desired result. This is where I'm stuck, not sure what I'm doing wrong. Thank you for your considerations.​




 
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