Prediction interval, which brackets?

likearollings
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Prediction interval, which brackets!?

Hi, this is a quick question for a piece of statistics coursework I am doing.

I have made a prediction interval with an upper bound of let's say 30 and lower of 20.

I just don't know which brackets to use open or close e.g.

(20,30)

[20,30]

(20,30]

[20,30)

I know its a bit of a stupid question :redface: and is maybe not worthy to be in this forum but I am pretty pedantic when it comes to coursework

Ok any help is appreciated.
 
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likearollings said:
Hi, this is a quick question for a piece of statistics coursework I am doing.

I have made a prediction interval with an upper bound of let's say 30 and lower of 20.

I just don't know which brackets to use open or close e.g.

(20,30)

[20,30]

(20,30]

[20,30)

I know its a bit of a stupid question :redface: and is maybe not worthy to be in this forum but I am pretty pedantic when it comes to coursework

Ok any help is appreciated.

If we're talking about a continuous distribution as opposed to a discrete distribution, I don't think it makes any difference. Pr(a < X < b) = Pr(a <= X < b) = Pr(a < X <= b) = Pr(a <= X <= b). IOW, the probability that a variable is a single value is zero, so including an endpoint of an interval or omitting it makes no difference.

The only thing I can think of where including/omitting an interval endpoint makes a difference is when your null hypothesis includes the endpoint.

Hope that helps.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

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