Preparing NaOH Reagent: Diluting 0.32M Solution with Water

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SUMMARY

The discussion centers on the preparation of a 0.32M NaOH solution through dilution. To achieve this, the correct method involves mixing 1 part of the 0.32M NaOH solution with 4 parts of distilled water, resulting in a total volume of 5 parts. The dilution formula cxv=cxv is applicable, but the problem lacks sufficient information to calculate specific volumes for different concentrations. The participants emphasize the importance of clarity in the problem statement regarding the availability of the reagent.

PREREQUISITES
  • Understanding of molarity and solution concentration.
  • Familiarity with dilution principles and calculations.
  • Knowledge of laboratory safety protocols when handling NaOH.
  • Basic skills in measuring liquid volumes accurately.
NEXT STEPS
  • Research the principles of solution dilution and concentration calculations.
  • Learn about the properties and handling of sodium hydroxide (NaOH) in laboratory settings.
  • Explore the use of volumetric flasks for accurate solution preparation.
  • Study the implications of solution concentration on chemical reactions.
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Chemistry students, laboratory technicians, and anyone involved in preparing chemical solutions will benefit from this discussion.

Nanu Nana
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Homework Statement


There is a reagent given . NaOH with concentration of 0,32 mol/ L
HOw to prepare it ?
it says dilute 1 part by volume of solution Naoh with 4 parts by volume of redist.water ??
(Neglect the total volume that you need , it's not important ) just the process to make it

Homework Equations


cxv=cxv

The Attempt at a Solution


Is it correct if i say 1 mL of naoh solution and 4 ml of water ?
 
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Problem doesn't look complete to me. You say you have a reagent and you are asked to prepare it. You either have it, or you have to prepare it.

And dilution is used to prepare a solution with a lower concentration from a more concentrated solution. You listed only one concentration, so there is not enough information to calculate any dilutions.
 

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