Pressure in Garden Hose: Solving P + (1/2)pv^2 + pgh

[FlipStyle1308]

Am I substituting other variables into P + (1/2)pv^2 + pgh in this problem?

A garden hose is attached to a water faucet on one end and a spray nozzle on the other end. The water faucet is turned on, but the nozzle is turned off so that no water flows through the hose. The hose lies horizontally on the ground, and a stream of water sprays vertically out of a small leak to a height of 0.82 m. What is the gauge pressure inside the hose? (Gauge pressure is the amount by which the pressure exceeds atmospheric pressure.)

 

[Gokul43201]

That is the correct equation. All you have to do is compare between a point inside the hose (energy density in hose = P_in ) and the point at the top of the vertical spray (energy density at top = pgh + Po).

 

[FlipStyle1308]

Great, got the answer, thanks!