4.80×10^23 nitrogen molecules collide with a 16.0 cm^2 wall each second. Assume that the molecules all travel with a speed of 410 m/s and strike the wall head on. Answer in pascals
The Attempt at a Solution
Ordinarily I would use P=1/3(N/V)mv(rms)^2
but, I am not given the volume. I figure I should just use momentum/area / 1 second?
MV will give me Newton * Seconds. Since we are looking at just 1 second, it should work right?
Heres what I did:
Converted 6.022*10^23 molecules to grams by:
6.022*10^23 N2 / 6.022*20^23 * 28g = 22.318g = 0.0023Kg
Convert 16cm^2 to 0.0016m^2
(0.0023Kg)(410)/(0.0016m^2) = 5719 Pa
This answer is wrong tho.
What am I doing wrong here?