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## Homework Statement

Mercury is poured into a U-tube as shown in Figure a. The left arm of the tube has cross-sectional area

*A*of 11.0 cm

_{1}^{2}, and the right arm has a cross-sectional area

*A*

_{2}of 4.60 cm

^{2}. One hundred grams of water are then poured into the right arm as shown in Figure b.

The length of the column of water is 21.7 cm.

Given that the density of mercury is 13.6 g/cm3, what distance

*h*does the mercury rise in the left arm?

## Homework Equations

V

_{1}= V

_{2}

P = P

_{0}+ pgh

## The Attempt at a Solution

I honestly have no clue where to start. Finding the length of the column of water was easy, but I don't really know what to do from here.