1. The problem statement, all variables and given/known data Mercury is poured into a U-tube as shown in Figure a. The left arm of the tube has cross-sectional area A1 of 11.0 cm2, and the right arm has a cross-sectional area A2 of 4.60 cm2. One hundred grams of water are then poured into the right arm as shown in Figure b. The length of the column of water is 21.7 cm. Given that the density of mercury is 13.6 g/cm3, what distance h does the mercury rise in the left arm? 2. Relevant equations V1 = V2 P = P0 + pgh 3. The attempt at a solution I honestly have no clue where to start. Finding the length of the column of water was easy, but I don't really know what to do from here.