Presumably simple logarithm equationt

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SUMMARY

The equation 6 \cdot e2x = 4x can be solved by taking the natural logarithm of both sides. The correct approach involves applying the logarithmic identity for products, leading to ln(6) + 2x = x ln(4). The solution can be simplified to find the value of x, which is given as ln(6) / (ln(4) - 2). This method corrects the initial misunderstanding of moving constants to the exponent.

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Homework Statement



What value of x satisfies the equation:

6 \cdot e2x = 4x

The Attempt at a Solution



If I'm not mistaken, I can move the 6 to the superscripted part of e, resulting in:

e12x = 4x

And then I can take the natural log of both sides, resulting in:

12x = ln(4x)

Assuming I haven't made any mistakes, this is what I have so far and I'm stuck. This is for a practice test and I have the answer listed as:

ln6 / (ln4 - 2)

I'm just not sure how to get there.
 
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Chase. said:

Homework Statement



What value of x satisfies the equation:

6 \cdot e2x = 4x

The Attempt at a Solution



If I'm not mistaken, I can move the 6 to the superscripted part of e, resulting in:

e12x = 4x

You are mistaken. You can't do that. E.g. 2*32 = 18 ≠ 34 = 81.


Chase. said:
And then I can take the natural log of both sides, resulting in:

12x = ln(4x)

Just start with taking the ln of both sides right from the beginning:

ln(6*e2x) = ln(4x)

The log of a product is the sum of the logs:

ln6 + 2x = xln4

Can you take it from here?
 

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