MHB Prime Versus Irreducible Numbers

  • Thread starter Thread starter Panda1
  • Start date Start date
  • Tags Tags
    Numbers Prime
AI Thread Summary
A natural number p greater than 1 is defined as irreducible if for any natural numbers a and b, p dividing the product ab implies that p divides either a or b. The discussion centers on proving that if p is irreducible, then the equation p = ab leads to either p = a or p = b. The proof involves demonstrating that if p divides a or b, it must equal one of them due to their positive nature. This establishes that irreducible numbers greater than 1 are indeed prime. The conversation highlights the connection between irreducibility and primality in natural numbers.
Panda1
Messages
1
Reaction score
0
I don't quite know where to start with this one:

"A natural number p>1 is called irreducible if it has the property that, for any natural numbers a and b, p|ab always implies that either p|a or p|b (or both).

Prove that if a natural number p>1 is irreducible, then it also has the property that p=ab always implies that either p=a or p=b."

I figured that I essentially need to prove that irreducible natural numbers greater than 1 are prime.

Any help with this would greatly appreciated especially since I'm rather new to this site.
 
Mathematics news on Phys.org
Hi Panda,

Let $p$ be irreducible; let $a, b$ be natural numbers such that $p = ab$. Then $p | ab$, which implies $p | a$ or $p | b$ by irreducibility of $p$. If $p | a$, then since $a | ab = p$ we have $p = \pm a$. Since $p$ and $a$ are positive, $p = a$. Similarly if $p | b$, then since $b | p$ we deduce $p = b$.
 
Seemingly by some mathematical coincidence, a hexagon of sides 2,2,7,7, 11, and 11 can be inscribed in a circle of radius 7. The other day I saw a math problem on line, which they said came from a Polish Olympiad, where you compute the length x of the 3rd side which is the same as the radius, so that the sides of length 2,x, and 11 are inscribed on the arc of a semi-circle. The law of cosines applied twice gives the answer for x of exactly 7, but the arithmetic is so complex that the...
Thread 'Imaginary Pythagoras'
I posted this in the Lame Math thread, but it's got me thinking. Is there any validity to this? Or is it really just a mathematical trick? Naively, I see that i2 + plus 12 does equal zero2. But does this have a meaning? I know one can treat the imaginary number line as just another axis like the reals, but does that mean this does represent a triangle in the complex plane with a hypotenuse of length zero? Ibix offered a rendering of the diagram using what I assume is matrix* notation...
Fermat's Last Theorem has long been one of the most famous mathematical problems, and is now one of the most famous theorems. It simply states that the equation $$ a^n+b^n=c^n $$ has no solutions with positive integers if ##n>2.## It was named after Pierre de Fermat (1607-1665). The problem itself stems from the book Arithmetica by Diophantus of Alexandria. It gained popularity because Fermat noted in his copy "Cubum autem in duos cubos, aut quadratoquadratum in duos quadratoquadratos, et...
Back
Top