Prisim and angle of deviation problem

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SUMMARY

The discussion focuses on calculating the angles related to light refraction through a fused quartz prism with an apex angle of 60.0° and a refractive index of 1.459. The user successfully determined the angle of refraction at the first surface (41.9°), the angle of incidence at the second surface (18.1°), and the angle of refraction at the second surface (27.0°) using Snell's Law and geometric principles. However, the user seeks clarification on calculating the angle between the incident and emerging rays, which is essential for determining the angle of deviation.

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buttterfly41
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Light of wavelength 700 nm is incident on the face of a fused quartz prism at an angle of 77.0° (with respect to the normal to the surface). The apex angle of the prism is 60.0°. n=1.459.

a) the angle of refraction at the first surface
(b) the angle of incidence at the second surface
(c) the angle of refraction at the second surface
(d) the angle between the incident and emerging rays

i understand the first three by using geometry and snells law.. answers fro a) 41.9, for b) 18.1, for c)27.0. But i do not understand how to obtain the answer for part d. I thought it was asking for the angle of deviation in essence i thought , which is abs(theata1 - theata2). but other than that guess i don't know where else to take it from.

Any help would be wonderful. thankyou.
 
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Try drawing a diagram of the ray path and it will help you see how to get the angle.
 

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