Probability a five-card contains the ace of hearts

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SUMMARY

The probability of drawing a five-card hand that contains the Ace of Hearts is calculated using combinatorial methods. The formula used is P(E) = |E|/|S|, where |E| represents the number of favorable outcomes and |S| the total outcomes. The calculation involves choosing the Ace of Hearts and then selecting 4 additional cards from the remaining 51 cards, resulting in the expression 1 * C(51, 4) / C(52, 5). This method provides a clear and definitive approach to solving the problem.

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Homework Statement


What is the probability that a five-card contains the ace of hearts?

Homework Equations


[tex]P(E)=|E|/|S|[/tex]
[tex]P(E_{1}\bigcup E_{2})=P(E_{1})+P(E_{2}) + P(E_{1}\bigcap E_{2})[/tex]

The Attempt at a Solution


The number of ways to choose 5 cards from 52*the numbers of ways to get an ace from five of those?
[tex]C(52,5)C(5,1)[/tex]
 
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mmm, try:

number of ways to choose ace of hearts*number of ways to choose the other 4 cards/number of ways to choose 5 cards from 52.

1*c(51,4)/c(52,5)

that seems better to me.
 
That looks better, thank you very much.
 

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