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## Homework Statement

Suppose that a dietitian has 3 groups of foods, having 5 items in the first group, 7 items in the second group and 2 items in the third group.

1. How many meals are possible containing one food from each food group?

2. How many meals are possible containing 3 foods from the first group and none from the other two groups

3. How many meals are possible containing 2 foods from the first group, 3 from the second group and none from the third group?

4. How many meals are possible containing 4 foods from first group, 4 from the second and 1 from the third group?

## The Attempt at a Solution

1. 5x7x2= 70. Is this right?

2. 3x5= 15, Is this right?

3. 2x5= 10 for first group, 3x7=21 for second group. So total would be 10x21= 210 meals possible?

4. 4x5= 20, 4x7= 28, 1x2= 2. Then do u multiply all of these three values?

Please help