Probability distribution function question

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SUMMARY

The discussion centers on the cumulative distribution function (CDF) F(x) of a continuous random variable X, defined piecewise for the interval [0,1]. The function is specified as F(x) = 0 for x<0, F(x) = x for 0<=x<0.25, F(x) = 0.25 for 0.25<=x<0.5, F(x) = x² for 0.5<=x<1, and F(x) = 1 for x>=1. A participant questions the logic behind F(x) being equal to 1 for x>1 and seeks clarification on calculating probabilities such as P(X>0.75) when F(x) reaches its maximum value.

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Homework Statement


A PC generates "random" numbers from [0,1], programmed such that
the distribution function F(x) of a continuous random variable X, which is satisfies the formula:

F(x) =
0 , x<0
x , 0<=x<0.25
0.25 , 0.25<=x<0.5
x2, 0.5<=x<1
1 , 1<=x

THe problem then asks the values of probabilities in ranges of X.

Homework Equations


-

The Attempt at a Solution


My question is, why is F(x) , x>1 = 1?
Isn't that, you know, non sensical?

And, how, for example will i measure the P(x>.75), when F(x)=1 for x>1 ?
(edit: or is big F of x, a standard notation for the cumulative distr. function?)
 
Last edited:
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Ah, never mind.
It is the cumulative distribution function, both my teacher and textbook had the great idea of calling it "ditribution function"
Dammit.

delete if you want
 
Last edited:

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