MHB Probability of a random subset of Z

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To calculate the probability of a random subset B of Z being a proper subset of A, the number of proper subsets of A must be divided by the total number of subsets of Z. Since A has four elements, it has 15 proper subsets. The total number of subsets of Z, which has ten elements, is 2^10 or 1024. For the second part, the condition A ∩ B = Ø means that B must be a subset of the complement of A within Z, which consists of the elements {5, 6, 7, 8, 9, 10}. Understanding these probabilities requires recognizing the equal likelihood of selecting any subset from Z.
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I'm stuck in this question, could someone give me a hand?

Question 9:
Let $$A = (1,2,3,4)$$ and $$Z = (1,2,3,4,5,6,7,8,9,10)$$, if a subset B of Z is selected by chance calculate the probability of:

a) $$P (B⊂A)$$ B is a proper subset of A
b) $$P (A∩B = Ø)$$ A intersection B =empty set
Appreciate
 
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Statistics4win said:
if a subset $B$ of $Z$ is selected by chance
This may mean different things. What are probabilities of selecting individual subsets if $Z$? If all such probabilities are equal, i.e., if each subset is equally likely, then $P(B\subset A)$ equals the number of proper subsets of $A$ divided by the number of all subsets of $Z$. For the number of subsets see Powerset in Wikipedia. For b) note that $A\cap B=\emptyset\iff B\subseteq Z\setminus A$.
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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