Probability of birthdays on every day

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In summary: The probability that at least one person has a birthday on every single day in a 365 day year is approximately 0.997. In summary, the conversation discusses the probability of having one birthday on every single day in a 365 day year given a randomly selected group of 430 people. The conversation also touches on the factors that can affect the distribution of births throughout the year. The probability, also known as the "Coupon Collector's Problem", is approximately 0.997.
  • #1
duzza275
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Please may someone help me with this and if you have an answer please may you show all the steps that you took. This is not a prep question but I was thinking about it and wondering what the answer was but my statistics skills are not good enough for this yet. :)

If I have a randomly selected group of 430 people. What is the probability that there is 1 birthday on ever single day in the year? (Assume that it is a 365 day year)

Thanks
 
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  • #2
Good luck...I guess you are asking for an answer from the purely mathematical point of view assuming a uniform distribution of births throughout the year?

I am wondering because that's not what REALLY happens. Weather and holidays affect love-making; last I heard, new year's is a 'lucky' day and so, we have a lot of September people.

Just look at the animal kingdom; ok, they don't have holidays, but look at how the times when, basically, the entire group gives birth within a matter of days or weeks ruled by migratory patterns, availability of food, weather conditions, etc.

Anyway, just a thought.
 
  • #3
Yeh I am looking for an answer with a mathematical point of view that assumes that births are evenly distributed throughout the year.
 
  • #4
duzza275 said:
Please may someone help me with this and if you have an answer please may you show all the steps that you took. This is not a prep question but I was thinking about it and wondering what the answer was but my statistics skills are not good enough for this yet. :)

If I have a randomly selected group of 430 people. What is the probability that there is 1 birthday on ever single day in the year? (Assume that it is a 365 day year)

Thanks

This is the "Coupon Collector's Problem". See my reply to this post

https://www.physicsforums.com/showthread.php?t=523620

for a formula for the probability.
 
  • #5
for your question! This is a great example of using probability to analyze a real-world situation. To solve this problem, we need to use the concept of independent events.

First, let's define the event we are interested in: having 1 birthday on every single day in a 365-day year. This means that each person in the group has a unique birthday, and no two people share the same birthday.

Next, we need to calculate the total number of possible outcomes for this event. Since there are 365 days in a year, and we have 430 people, the total number of possible outcomes is 365^430. This is a very large number, but it represents all the possible combinations of birthdays that could occur in this group.

Now, let's look at the favorable outcomes, or the outcomes that meet our criteria of having 1 birthday on every day. To calculate this, we can use the formula for combinations, nCr, which represents the number of ways to choose r objects from a set of n objects without replacement. In this case, n=365 and r=430, so the formula becomes 365C430 = 365! / (430!(365-430)!). This results in a very small number, indicating that the number of ways to have 1 birthday on every day is much smaller than the total number of possible outcomes.

Finally, we can calculate the probability by dividing the number of favorable outcomes by the total number of possible outcomes: 365C430 / 365^430. This gives us a probability of approximately 0.000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000
 

1. What is the probability of two people having the same birthday?

The probability of two people having the same birthday (assuming a non-leap year and an equal distribution of birthdays) is approximately 1 in 365 or 0.27%. This may seem low, but in a group of 23 people, there is a greater than 50% chance that two people will share the same birthday.

2. How is the probability of shared birthdays calculated?

The probability of shared birthdays can be calculated using the formula P(n) = 1 - (365!/((365-n)!*365^n)), where n is the number of people in the group. This formula takes into account the number of possible combinations of birthdays and the total number of days in a year.

3. Does the probability change if the group size increases?

Yes, the probability of shared birthdays increases as the group size increases. This is due to the fact that there are more possible combinations of birthdays as the number of people in the group increases, making it more likely for two people to share the same birthday.

4. Is the probability affected by the distribution of birthdays in a population?

Yes, the probability can be affected by the distribution of birthdays in a population. For example, if there is a higher concentration of birthdays in a certain month or season, the probability of shared birthdays may increase.

5. How does the concept of probability of shared birthdays relate to real-life situations?

The concept of probability of shared birthdays can be applied to various real-life situations, such as scheduling events or meetings. Knowing the probability can help in avoiding conflicts and ensuring a larger turnout. It can also be used in fields such as cryptography to estimate the likelihood of two people generating the same random number or password.

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