Probability of drawing two married couples

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Homework Help Overview

The problem involves calculating the probability of drawing a married couple from a set of names representing four married couples. The specifics of the drawing process, whether simultaneous or sequential, are not clearly defined.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the probability calculations, questioning the necessity of drawing a woman first and exploring different interpretations of the drawing process. Some suggest that the total combinations of couples and the method of drawing affect the probability.

Discussion Status

The discussion is active, with participants providing various interpretations of the problem setup and probability calculations. Some guidance has been offered regarding the implications of drawing from a single container versus separate containers for men and women.

Contextual Notes

There is ambiguity in the problem regarding the drawing method and whether the cards are drawn simultaneously or one-by-one, which participants are addressing. Additionally, the lack of clarity on whether to consider gender in the drawing process is being discussed.

turutk
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Homework Statement



Names of 8 people (4 married couples) are written down to equally sized papers. Two carbilds are drawn. What is the probability of drawing a married couple? (it is not specified if the cards were drawn at the same time or one-by-one)


Homework Equations



na

The Attempt at a Solution



So the probability of drawing a woman is 4/8 the probability of drawing her husband is 1/7 when multiplied the result is 1/14 but the correct answer is 1/7. (non combination solution would be better)
 
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hi turutk! :smile:
turutk said:
So the probability of drawing a woman is 4/8 …

why does it have to be a woman? :wink:
 
i thought it wouldn't matter but now i think that i need to multiply 1/12 by 2.

also i got the solution. 4 married couples could be drawn. a total of 8C2 can be drawn. 4/8C2 = 1/7


thanks for your answer
 
Yes, it does matter. Actually, you question is a little ambiguous. Do you put all 8 names in the same container so you might draw two men or two women, or do you draw men and women separately? Drawing "one by one" or "both at the same time" does NOT matter.

Assuming all 8 are put into a single container, you draw one name. Now, there are seven names left and exactly one of those is the first person's spouse. What is the probability of that spouse being drawn?

If all four men are put into one container and all four women in another, it's slightly different. You draw a person from one container (whether it is a man or a woman doesn't matter). Now there are four people left in the other container and one of them is the first person's spouse. What is the probability now?
 
names of 8 people are put into a box and 2 cards are drawn. so it can be woman-woman, woman-man, man-woman, man-man
 

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