Probability of Drop Chances on Wow Items

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SUMMARY

The discussion focuses on the probability of drop chances for items in World of Warcraft (WoW), using coin tosses as a metaphor for understanding probabilities. The probability of getting at least one "heads" in two coin tosses is calculated as 0.75, derived from the formula 1 - (0.5 * 0.5). Furthermore, over 100 tosses, the probability of getting at least one "heads" approaches 99.999999999999999999999999999921%. This illustrates the concept of cumulative probability in gaming scenarios.

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  • Understanding of basic probability concepts
  • Familiarity with cumulative probability calculations
  • Knowledge of World of Warcraft item mechanics
  • Basic statistical analysis skills
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  • Research "Cumulative Probability in Gaming" to understand its applications
  • Learn about "Probability Distributions" and their relevance in game mechanics
  • Explore "Statistical Analysis in Game Design" for deeper insights
  • Study "Monte Carlo Simulations" for predicting drop rates in games
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This discussion is beneficial for game developers, statisticians, and players interested in understanding item drop mechanics and probabilities in World of Warcraft and similar games.

BenVitale
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Drop chance probability

http://www.wow.com/2010/01/13/drop-chance-probability/


For some reason, the explanation provided in that document is not clear to me.

Could anyone offer a different explanation?
 
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Tossing a fair coin.

The probability of "heads in the first throw" is 0.5.
The probability of "heads in the second throw" is 0.5.
The probability of "(one or more) heads in the first two throws" is equal to "probability of HH + probability of HT + probability of TH" = 1 - probability of TT = 1 - ("probability of tails in the first throw" times "probability of tails in the second throw") = 1 - (0.5 times 0.5) = 1 - 0.5^2 = 0.75.

Note that if "probability of heads" = x then "probability of tails" = 1 - x. In my example x = 1 - x = 0.5.
 
So,

flip But over the course of 100 tosses, the probability of getting heads is way more than 50%. (In fact, the chance is 99.999999999999999999999999999921% that we'll get heads at least once.)

translates into the probability of at least one Heads appears in "y" throws.

In your example y = 2, and we know that x = 1/2
 

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