Probability of getting 4 white beads

[juls]

Bag A contains 6 white beads and 3 black beads. Bag B contains 6 white beads and 4 black beads. One bead is chosen at random from each bag. A second bead is chosen at random from each bag. Find the probability that, all four beads are white.

I am not sure if the answer is P(WWWW), in which case we use multiplication, or P (ww) and P2 (WW).

i think the answer is (6/9 X 5/8) + (6/10 X 5/9) = 0.75
but there's a chance it might be (6/9 *5/8 *6/10 *5/9)

I NEED HELP!

 

[arildno]

Remember that whatever your result from drawing two beads from bag A is INDEPENDENT from drawing two beads from bag B.