Probability IB Math HL: Is it a difficult question to solve?

  • Context: High School 
  • Thread starter Thread starter coolfish21
  • Start date Start date
  • Tags Tags
    Ib Probability
Click For Summary

Discussion Overview

The discussion revolves around a probability problem involving drawing cards without replacement from a bag containing cards numbered from 1 to 6. Participants explore the challenge of calculating the probability that the sum of 8 drawn cards equals 28, considering the given probabilities for each card number.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • A participant presents the problem of calculating the probability that the sum of 8 cards drawn from a bag equals 28, providing the probabilities for each card number.
  • Another participant questions the origin of the problem and suggests that it may require complex casework, noting that the problem would be simpler if replacement were allowed.
  • A participant expresses difficulty in finding a solution and suggests using a computer program to assist in solving the problem.
  • One participant proposes that the first step should be to list all combinations of card draws that sum to 28, indicating that calculating the probability for each case would then be straightforward.

Areas of Agreement / Disagreement

Participants do not appear to reach a consensus on the best approach to solve the problem, with differing opinions on the complexity and methods required.

Contextual Notes

The discussion highlights the potential need for casework and the challenges posed by the lack of replacement in the card drawing process. There are unresolved steps regarding how to systematically approach the problem.

coolfish21
Messages
1
Reaction score
0
TL;DR
I have not been able to figure out the solution. Can anyone help me with this?

A person picks 8 cards without replacement from a bag containing cards numbered from 1 to 6 (117 in total). What is the probability that the sum of those 8 cards is 28? Given that P(1)=8/117, P(2)=14/117, P(3)=34/117, P(4)=39/117. P(5)=14/117 and P(6)=8/117.
A person picks 8 cards without replacement from a bag containing cards numbered from 1 to 6 (117 in total). What is the probability that the sum of those 8 cards is 28? Given that P(1)=8/117, P(2)=14/117, P(3)=34/117, P(4)=39/117. P(5)=14/117 and P(6)=8/117.
 
Physics news on Phys.org
Where does this problem come from?
What did you try so far?
This will probably need ugly casework. With replacement it would be much easier.
 
coolfish21 said:
Summary:: I have not been able to figure out the solution. Can anyone help me with this?

A person picks 8 cards without replacement from a bag containing cards numbered from 1 to 6 (117 in total). What is the probability that the sum of those 8 cards is 28? Given that P(1)=8/117, P(2)=14/117, P(3)=34/117, P(4)=39/117. P(5)=14/117 and P(6)=8/117.

A person picks 8 cards without replacement from a bag containing cards numbered from 1 to 6 (117 in total). What is the probability that the sum of those 8 cards is 28? Given that P(1)=8/117, P(2)=14/117, P(3)=34/117, P(4)=39/117. P(5)=14/117 and P(6)=8/117.
I suggest you write a computer program to do it.
 
First step: list all combination which add to 28. The probability in each case is straightforward. Then add.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 9 ·
Replies
9
Views
5K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 41 ·
2
Replies
41
Views
6K
  • · Replies 10 ·
Replies
10
Views
3K