Probability of Girl in Family of 3 Children

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SUMMARY

The probability of having at least one girl in a family of three children, given that the eldest child is a boy and there is at least one other boy, is calculated to be 2/3. The possible combinations of children are BBB, BBG, BGB, and BGG. However, since BGG is eliminated due to the condition of having at least one boy, the remaining combinations (BBB, BBG, BGB) show that two out of three scenarios include at least one girl. Therefore, the correct probability is not 0.5, but rather 2/3, emphasizing the importance of understanding conditional probabilities in this context.

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jackbauer
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Hi people.
I have a short question from a homework. given a family with 3 children, the sexes of which are unknown: if the eldest child is a boy and there is at least one other boy, then what is the probability one child is a girl?
To me it seems obvious that there are at least two boys from this info, then either there are 3 boys or 2 boys and 1 girl, so the probability one child is a girl is 0.5. Is this method correct?
Thanks,
JB
 
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A family with three children and the eldest is a boy. Writing B for boy, G for girl, from oldest to youngest, the possibilities are:
BBB
BBG
BGB
BGG
Assuming "boy" or "girl" are equally likely at each birth, these are equally likely.

But we are told that at least one child is a boy: that throws out BGG leaving
BBB
BBG
BGB and they are still equally likely.
Since 2 of those 3 correspond to "one child is a girl", the probability that one of the children is a girl is 2/3, not 1/2. Yes, it is true that there must be "either 3 boys or 2 boys and a girl", but those are NOT "equally likely".
 
As far as I'm concerned you should better explain the underlying reason: probability of each sex child birth is fifty-fifty. In a formal proof is often request.
 

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