Probability of r heads in n fair coin tosses

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Ryoukomaru
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An unbiased coin is tossed n times and X is the number of heads obtained. Write down an expression for the probability that X=r.

It looks so simple yet I can't figure it out.
Does it follow a binomial distribution ?

Then if
[tex] X[/tex]~[tex]N (n,p)[/tex]

It follows
[tex] P(X=r) = \left(<br /> \begin{array}{cc}<br /> n\\<br /> r<br /> \end{array}<br /> \right)<br /> \cdot p^r \cdot q^{n-1}[/tex]
where [tex]q=1-p[/tex]

But [tex]p=q=1/2[/tex]
So the answer is
[tex] P(X=r) = \left(<br /> \begin{array}{cc}<br /> n\\<br /> r<br /> \end{array}<br /> \right)<br /> \frac{1}{2}^{r+n-1}[/tex]

Am I right ?

P.S. First time using latex. It sure took long. :-p
 
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when u raise the fraction by a certain power, u have to distribute the power to both the numerator and denominator
 
Ryoukomaru said:
[tex] P(X=r) = \left(<br /> \begin{array}{cc}<br /> n\\<br /> r<br /> \end{array}<br /> \right)<br /> \cdot p^r \cdot q^{n-1}[/tex]
where [tex]q=1-p[/tex]
Almost. q should be raised to the (n-r)th power.

P.S. First time using latex. It sure took long. :-p
You'll get used to it. And it looks so pretty. :biggrin:

By the way, you don't need to use array's for displaying [itex]n \choose r[/itex]. LateX has a special command for it. Just type {n \choose r}. You can even omit the brackets.
 
Ahh right, thanks for the correction. Silly me.

Gallieo: Thx for the tip. :)
I got to read through the list of latex commands but i am so busy right now, i don't have time for it.