Probability of X being greater than Y for independent uniform variables

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SUMMARY

The probability of X being greater than Y for independent uniform variables X and Y, both uniformly distributed over the set {1, 2, ..., M}, is calculated as P(X > Y) = (M + 1) / (2M). For M = 3, the matrix representation shows the conditions where X exceeds Y, confirming the formula's validity. The total number of cases is M^2, and the satisfied conditions can be counted directly from the matrix.

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magnifik
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Let X and Y be independent and uniform on {1, 2, ... M}
Find P(X > Y)

so i know that P(X = x) = 1/M and P(Y = y) = 1/M
i don't understand how Find P(X > Y) = (M+1)/2M
 
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Hi magnifik! :smile:

Suppose M=3.

Then we have the matrix:
Code:
X\Y   1  2  3
1     ≥
2     ≥  ≥
3     ≥  ≥  ≥

In how many cases is the condition satisfied?
And what is the total number of cases?
 

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