Probability per atom and per second for stimulated emission to occur

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SUMMARY

The discussion focuses on calculating the probability per atom and second for stimulated emission from the 2p to 1s state of hydrogen in a plasma at 4500 ºC. The lifetime of the 2p state is given as 1.6 ns, leading to an initial calculation of the Einstein A coefficient, A = 6.25 x 108 s-1. The participants explore the relationship between radiation density, temperature, and the necessary coefficients for stimulated emission, utilizing Planck’s radiation law and statistical mechanics to derive the required values.

PREREQUISITES
  • Understanding of Einstein coefficients (A and B) in quantum mechanics
  • Familiarity with Planck’s radiation law and its application
  • Knowledge of statistical mechanics, particularly the Boltzmann distribution
  • Basic concepts of atomic transitions and lifetimes
NEXT STEPS
  • Research the derivation and application of Einstein A and B coefficients
  • Study Planck’s radiation law in detail, focusing on its implications for atomic emissions
  • Explore the Boltzmann distribution and its role in population ratios of atomic states
  • Investigate the Doppler line width and its relevance in plasma physics
USEFUL FOR

Physicists, particularly those specializing in atomic and plasma physics, as well as students working on quantum mechanics and thermodynamics related to atomic transitions.

Philip Land
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Homework Statement


We are investigating hydrogen in a plasma with the temperature 4500 ºC. Calculate the probability per atom and second for stimulated emission from 2p to 1s if the lifetime of 2p is 1.6 ns

Homework Equations


##A=\frac{1}{\Sigma \tau}##

$$A_{2,1} = \frac{8*\pi *h * f^3*B_{2,1}}{c^3}$$

The Attempt at a Solution


[/B]
hmmm, I'm not sure how to approach this problem. I took the inverse of the life time and got that A= ##6.25*10^8 S^{-1}.##

But I'm not sure where to start or what formulas to use.

The only formula I know of which takes temperature into account is
Doppler line width: ##\Delta F = constant * f_0 * \sqrt(T/M) ## which I can't see how to apply in this case at all.

Any input on where to start?
 
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The probability of stimulated emission will depend on the density of radiation around the atom, which depends on the temperature.
 
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mfb said:
The probability of stimulated emission will depend on the density of radiation around the atom, which depends on the temperature.
Thanks a lot! I manage to as you said find a relation between radiation density and temperature, (Planck’s radiation law).

Then I used a Radiation balance and solved for ##A_{21} = \rho (f) * \frac{N_1}{N_2}*B_{12}
-B{21}*\rho (f). ##

Where ##g_1*B_{12} = g_2*B_{21}## if we let g1=g2 we get ##B_{12}=B_{21}##

We also know from statistics that ##\frac{N_1}{N_2}= e^\frac{- \Delta E}{kT}##

But my question is. To get A (which I guess I'm supposed to get). I need B and ##\Delta E## But I don't have those quantities... (as I'm aware of).
 
Did you use the given lifetime already?
 
mfb said:
Did you use the given lifetime already?
Yes I used that to get the frequency, used in Plancks radiation law.
 
Philip Land said:
##A_{21} = \rho (f) * \frac{N_1}{N_2}*B_{12} -B{21}*\rho (f). ##
It might help to rearrange this equation as ##N_2A_{21} + N_2B_{21}\rho (f)= N_1B_{12}\rho (f) ##.
Interpret each of the terms. One of the terms is closely related to what you are asked to find.
 

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