Probability Problems: P(X≤15)=0.3, P(15<X≤24)=0.6, P(X>20)=0.5

[Mesmer]

Let $$P(X\leq \15)= 0.3, P(15\less X \leq24)=6$$ and (P X > 20) = 0.5I don't understand how I would find this probability: $$P(15\lessX\leq20$$

The answer is 0.2.

 

[radou]

Are you sure you posted the problem correctly? The probability of an event cannot equal 6, first of all.

 

[Mesmer]

You are correct, the problem is not posted correctly. My latex coding is lacking...I wish there were a way a could delete this post.

 

[cristo]

Is it meant to be 0.6 by any chance? Thus, is your first equation meant to be $$P(X\leq \15)= 0.3,\ \ P(15< X \leq24)=0.6,\ \ P(X>20)=0.5$$, and you want to find $$P(15< X \leq20)$$?