Probability Problems: P(X≤15)=0.3, P(15<X≤24)=0.6, P(X>20)=0.5

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The discussion centers on the calculation of probabilities in a given problem where P(X≤15)=0.3, P(1520)=0.5. A participant identifies an error in the original post, noting that a probability cannot exceed 1, suggesting that P(15 PREREQUISITES

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Mesmer
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Let P(X\leq \15)= 0.3, P(15\less X \leq24)=6 and (P X > 20) = 0.5I don't understand how I would find this probability: P(15\lessX\leq20

The answer is 0.2.
 
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Are you sure you posted the problem correctly? The probability of an event cannot equal 6, first of all.
 
You are correct, the problem is not posted correctly. My latex coding is lacking...I wish there were a way a could delete this post.
 
Is it meant to be 0.6 by any chance? Thus, is your first equation meant to be P(X\leq \15)= 0.3,\ \ P(15&lt; X \leq24)=0.6,\ \ P(X&gt;20)=0.5, and you want to find P(15&lt; X \leq20)?
 

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