MHB Probability question involving finding gain or loss of a game

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The discussion revolves around a probability question related to calculating the gain or loss in a game. A user attempted a calculation using the formula $\frac{1}{13}$ x 30 + $\frac{12}{13}$ x $\frac{47}{51}$ x -10 but found it incorrect. Another participant asserts that the correct answer is 2/9 p, questioning the validity of the initial calculation. The original poster confirms they have the answer but are unsure of the solving process. The conversation highlights confusion over the correct method to arrive at the solution.
Milly
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I tried using $\frac{1}{13}$ x 30 + $\frac{12}{13}$ x $\frac{47}{51}$ x -10 but it didnt work.
 

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Milly said:
I tried using $\frac{1}{13}$ x 30 + $\frac{12}{13}$ x $\frac{47}{51}$ x -10 but it didnt work.

Hi Milly! (Smile)

I believe you already have the right answer.
What makes you say that it doesn't work?
 
It is not the right answer. The right answer is 2/9 p
 
Milly said:
It is not the right answer. The right answer is 2/9 p

How do you know what the right answer is?
 
This is actually a past exam question. I got the answer but I don't know how to solve it.
 
Seemingly by some mathematical coincidence, a hexagon of sides 2,2,7,7, 11, and 11 can be inscribed in a circle of radius 7. The other day I saw a math problem on line, which they said came from a Polish Olympiad, where you compute the length x of the 3rd side which is the same as the radius, so that the sides of length 2,x, and 11 are inscribed on the arc of a semi-circle. The law of cosines applied twice gives the answer for x of exactly 7, but the arithmetic is so complex that the...