Probability Question - Prove Formula

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SUMMARY

The discussion focuses on proving the probability formula P(A ∪ B | C) = P(A | C) + P(B | C) - P(A ∩ B | C). The user initially attempts to derive the formula using P(A ∪ B | C) = (P(A ∪ B)P(C | A ∪ B)) / P(C) but struggles due to a misunderstanding of the independence of events A, B, and C. Ultimately, the user recognizes that the events are not necessarily independent, which clarifies their approach to the proof.

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  • Knowledge of the principles of union and intersection of events
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Homework Statement



Hi,

Prove P(AUB|C) = P(A|C)+P(B|C)-P(A∩B|C)

Homework Equations





The Attempt at a Solution



I start off from here

[itex]P(AUB|C)=\frac{P(AUB)P(C|AUB)}{P(C)}[/itex]

I don't know where to go from here. Thanks for any help that you can provide.
 
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I think I actually figured this one. I realize that A, B, C may not necessairly be independent and for whatever reason I thought they where so I wasn't getting the correct answer
 

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